#!/bin/bash # pid-identifier.sh: # Gives complete path name to process associated with pid. ARGNO=1 # Number of arguments the script expects. E_WRONGARGS=65 E_BADPID=66 E_NOSUCHPROCESS=67 E_NOPERMISSION=68 PROCFILE=exe if [ $# -ne $ARGNO ] then echo "Usage: `basename $0` PID-number" >&2 # Error message >stderr. exit $E_WRONGARGS fi pidno=$( ps ax | grep $1 | awk '{ print $1 }' | grep $1 ) # Checks for pid in "ps" listing, field #1. # Then makes sure it is the actual process, not the process invoked by this script. # The last "grep $1" filters out this possibility. # # pidno=$( ps ax | awk '{ print $1 }' | grep $1 ) # also works, as Teemu Huovila, points out. if [ -z "$pidno" ] # If, after all the filtering, the result is a zero-length string, then #+ no running process corresponds to the pid given. echo "No such process running." exit $E_NOSUCHPROCESS fi # Alternatively: # if ! ps $1 > /dev/null 2>&1 # then # no running process corresponds to the pid given. # echo "No such process running." # exit $E_NOSUCHPROCESS # fi # To simplify the entire process, use "pidof". if [ ! -r "/proc/$1/$PROCFILE" ] # Check for read permission. then echo "Process $1 running, but..." echo "Can't get read permission on /proc/$1/$PROCFILE." exit $E_NOPERMISSION # Ordinary user can't access some files in /proc. fi # The last two tests may be replaced by: # if ! kill -0 $1 > /dev/null 2>&1 # '0' is not a signal, but # this will test whether it is possible # to send a signal to the process. # then echo "PID doesn't exist or you're not its owner" >&2 # exit $E_BADPID # fi exe_file=$( ls -l /proc/$1 | grep "exe" | awk '{ print $11 }' ) # Or exe_file=$( ls -l /proc/$1/exe | awk '{print $11}' ) # # /proc/pid-number/exe is a symbolic link #+ to the complete path name of the invoking process. if [ -e "$exe_file" ] # If /proc/pid-number/exe exists, then #+ then the corresponding process exists. echo "Process #$1 invoked by $exe_file." else echo "No such process running." fi # This elaborate script can *almost* be replaced by # ps ax | grep $1 | awk '{ print $5 }' # However, this will not work... #+ because the fifth field of 'ps' is argv[0] of the process, #+ not the executable file path. # # However, either of the following would work. # find /proc/$1/exe -printf '%l\n' # lsof -aFn -p $1 -d txt | sed -ne 's/^n//p' # Additional commentary by Stephane Chazelas. exit 0